Question

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find csa of closed cylindrical tank that is 4.2 in diameter and 4.5 m height​

Answer 1

$\sf\boxed{ \bold{given }}$

• height of cylinder = 4.5 m

• diameter of cylinder = 4.2 m

• radius = ½×(diameter) = 2.1 m

$\sf\boxed{ \bold{to \: find}}$

• curved surface area of cylinder(CSA)

$\sf\boxed{ \bold{solution}}$

we know,

$\red{\sf\boxed{ \bold{csa = 2\pi rh }}}$

$\sf\implies \: csa = 2 \times \frac{22}{7} \times 2.1 \times 4.5$

$\implies \sf \: csa = 44 \times 1.35$

$\bold{ \implies \: csa = 59.4 \: {m}^{2} }$