Question

$Wrong \: answer☺ = User \: 50 \: Answers \\ \: reported. \huge☠$
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Answer 1

Answer:

0

Step-by-step explanation:

$\displaystyle \sf\lim_{x \to 0} \frac{ \sin \: x - \tan { }^{ - 1}x }{x {}^{2} \log(1 + x) } \\ \\ : \implies \frac{ \sin \: 0 - { \tan}^{ - 1}0 }{(0) {}^{2} \log \: (1 + 0) {}^{2} } \\ \\ : \implies \frac{0 - \red{{ \tan}^{ - 1} { \tan}^{ - 1} }0}{0 \times \sf log(1) } \\ \\ \sf \boxed{\sf We \, Know \log 1 = 0} \\ \\ : \implies \: \frac{0 - 0}{0 \times 0} \\ \\ : \rightarrow \red{ \boxed{ \green{0}}}$

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Answer 2

Answer:

0 is the correct answer

hope it helps you