Question

(
${(x + 1)}^{2} + {( {x}^{2} + 3x + 2) }^{2} = 0$
what is the value of 'x'

Answer 1

Solution:-

${(x + 1)}^{2} + {( {x}^{2} + 3x + 2) }^{2} = 0 \\ ({x + 1)}^{2} + {( {x } ^{2} + 2x + x + 2)}^{2} = 0 \\ {(x + 1)}^{2} + {(x(x + 2) + 1(x + 2))}^{2} \\ {(x + 1)}^{2} + {(x + 2)}^{2} {(x + 1)}^{2} \\ {(x + 1)}^{2} (1 + {(x + 2)}^{2} )ans$