Math, asked by jainshalu43, 1 year ago


x = 1 +  \sqrt{2} find x ^{2}  + 1 \div x {}^{2}

Answers

Answered by priyanshu438
0

Step-by-step explanation:

x =1 +√2

x-1=√2

Squaring both side we get

x^2 + 1 -2=2

x^2=3

x=√3

ATQ

(√3)^2 +1/(√3)^2

3+1/3

3.33

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