Question

$x^{2} - 1 - 2a - a^{2}$
factorise​

Answer 1

Solution :

∴ x² - 1 - 2a - a²

= x² - (1 + 2a + a²)

= x² - (1 + a)²

= {x + (1 + a)} {x - (1 + a)}

= (x + 1 + a) (x - 1 - a)

= (x + a + 1) (x - a - 1)

Identity Rules :

• (a + b)² = a² + 2ab + b²
• a² - b² = (a + b) (a - b)

Method of factorization :

The easiest ways are to use middle-term method or by identity rules; maths vary only and other process may be used.

In identity rules method, we have to find a simpler form of terms where we will be able to use algebraic identities and then we do grouping by taking common terms out.

Answer 2

Answer:

$\huge\underline\mathfrak\purple{Solution}$