Question

${x }^{2} + 1 \div {x}^{2} = 27 \: find \: the \: value \: of \: x - 1 \div x$
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Answer 1

Step-by-step explanation:

${x}^{2} + \frac{1}{ {x}^{2} } = 27 \\ \\ {x}^{2} + {( \frac{1}{x}) }^{2} - 2(x)( \frac{1}{x} ) = 27 - 2 \\ {(x - \frac{1}{x}) }^{2} = 25 \\ x - \frac{1}{x} = 5$

That's the answer.

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