Question

$( {x}^{2} - 1) \times log(x) = \frac{1}{2}$
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Answer 1

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$( {x}^{2} - 1)log(x) = \frac{1}{2}$

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$( {x}^{2} - {1}^{2} )log(x) = \frac{1}{2}$

$logx = \frac{1}{2( {x}^{2} - {1}^{2}) }$

$logx = \frac{1}{2(x + 1)(x - 1)}$

Here is your answer^^^^^

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