Question

$x {}^{2} + 10x - 125 = 2x {}^{2} + 5x$
please solved it​

Answer 1

$\purple{ \huge \mathfrak{solution}}$

Given,

${x}^{2} + 10x - 125 = 2 {x}^{2} + 5x \\ = > 2 {x}^{2} - {x}^{2 } + 5x - 10x + 125 \\ = > {x}^{2} - 5x + 125 = 0$

Here a=1 , b =-5 and c=125

$x = \frac{ - b \pm \sqrt{b^{2} - 4ac } } {2a}$

put the values,

$= > \frac{ 5 \pm \sqrt{</strong><strong>2</strong><strong>5</strong><strong> - 500} }{2} \\ = > \frac{5 \pm \sqrt{ - 4</strong><strong>7</strong><strong>5} }{2}$

As we know that

$\sqrt{ - 1} = i$

then

x=

$\boxed{ \red{ \frac{5 + 4</strong><strong>7</strong><strong>5i}{2} }}$

and

x=

$\boxed{ \red{\frac{5 - 4</strong><strong>7</strong><strong>5i}{2} }}$

Answer 2

x^2+10x-125=2x^2+5x

=2x^2-x^2+5x-10x+125

=x^2-5x+125

solve it .

x= -(-5)+_√(-5)^2-4(1)(125)/2(1)

=5+_√-475/2

x=5+475i/2

and

x=5-475i/2