Question

$x {}^{2} - 12x + 32 = 0$
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Answer 1

Answer:

$x=8\:Or\:x=4$

Step-by-step explanation:

$Given\: quadratic\: equation:\\x^{2}-12x+32=0$

$\implies x^{2}-8x-4x+32=0$

$\implies x(x-8)-4(x-8)=0$

$\implies (x-8)(x-4)=0$

$\implies x-8=0\:Or\:x-4=0$

$\implies x=8\:Or\:x=4$

Therefore,

$x=8\:Or\:x=4$

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