Question

${x}^{2} + 12x + 32 = 0$
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Answer 1

Step-by-step explanation:

$given \: equation \: is \: {x}^{2} + 12x + 32 = 0 \\ \: = > {x}^{2} + 8x + 4x + 32 = 0 \\ \: = > x(x + 8) + 4(x + 8) = 0 \\ \: = > (x + 8)(x + 4) = 0 \\ \: = > (x + 8) = 0 \: or \: (x + 4) = 0 \\ \: x = - 8 \: and \: x = - 4$

Answer 2

Answer:

what we have to do in this question

I am unable to understand it which value we have to find in this question

hope you may understand it

Step-by-step explanation:

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