Math, asked by shantanugite, 8 months ago


 {x}^{2}  + 12x + 32 = 0

Answers

Answered by tennetiraj86
1

Step-by-step explanation:

given \: equation \: is \:  {x}^{2}  + 12x + 32 = 0 \\  \:  =  >  {x}^{2}  + 8x + 4x + 32 = 0 \\  \:   =  > x(x + 8) + 4(x + 8) = 0 \\  \: =  >  (x + 8)(x + 4) = 0 \\  \:  =  > (x + 8) = 0 \: or \: (x + 4) = 0 \\  \: x =  - 8 \: and \: x =  - 4

Answered by cinderella46
1

Answer:

what we have to do in this question

I am unable to understand it which value we have to find in this question

hope you may understand it

Step-by-step explanation:

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