Question

${x}^{2} - 14x + 120$
find x by factorization method​

Answer 1

Answer:

x^2-14x+120

x^2+20x-6x+120

x(x+20)-6(x+20)

(x+20)(x-6)

x=-20,6

mark me as brainliest and follow me friends

Answer 2

Correct Question:

Factorise the given expression and find x

${x}^{2} - 14x - 120$

Answer:

$\large\boxed{\sf{x=-6,20}}$

Step-by-step explanation:

Given to factorise

${x}^{2} - 14x - 120$

We will factorise it by splitting middle term

Therefore, we will get

$= {x}^{2} - 20x + 6x - 120 \\ \\ = {x}^{2} + 6x - 20x - 120$

Taking out common terms, we get

$= x(x + 6) - 20(x + 6) \\ \\ = (x + 6)( x- 20)$

Now, to find the value of x

=> x + 6 = 0

=> x = -6

And

=> x - 20 = 0

=> x = 20