Question

${x}^{2} - 15x + 54 = 0$

Answer 1

Hey here is your answer
x^2-15x+54
x^2-9x-6x+54
x (x-9)-6 (x-9)
(x-9)(x-6)
x=9
x=6

Answer 2

$x^2 - 15x + 54 = 0$

$x^2 -(9 + 6)x + 54 = 0$

$x^2 - 9x - 6x + 54 = 0$

x(x -9) -6(x -9) = 0

(x-9) (x-6) = 0

x -9 = 0   Or  x -6= 0       [By Zero-Product Rule]


x =9 Or x = 6 



i hope this will help you




-by ABHAY