Question

$x ^2 - 19x - 48 = 0$
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Answer 1

Answer:

38*8-#&&@[[¢×`°π€°•¶{[℅€=°~}€℅€™°2)) †; svh

Answer 2

Answer:

✍️${\huge{\pink{\underline{\underline{Question}}}}}$✍️

Find the root ofquadratic equation;

• ${x} ^{2} - 19x - 48 = 0$

✍️${\huge{\pink{\underline{\underline{Solution}}}}}$✍️

${x} ^{2} - 19x - 48 = 0$

$=>{x}^{2}-16x+3x-48=0$

$=>x(x-16)+3(x-16)=0$

$=>(x+3)(x-16)=0$

✈️So, the root of the equation${x} ^{2} - 19x - 48 = 0$ are

(x+3) and (x-16)✈️