Question

$x {}^{2} = 2(11 - 48) \: factorisation \: mehod$

Answer 1

${x}^{2} = 2(11 - 48) \\ \\ = > {x}^{2} = 2( - 37) \\ \\ = > {x}^{2} = - 74 \\ \\ = > x = \binom{ + }{ - } \sqrt{ - 74}$
______________________

Then,

=> X = -√74. and => X = √74

So factor is

=> (X - √74)(X + √74) = 0

________________[ANSWER]