Math, asked by vandesh, 1 year ago


x {}^{2}  + 2  \sqrt{2} x - 6 = 0 \: factorisation \: method

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Answered by TANU81
1
♥️Hi there ♥️

 {x}^{2}  + 2 \sqrt{2} x - 6 = 0  \\  \\  {x }^{2}   + 3 \sqrt{2} x -  \sqrt{2}  - 6 = 0 \\  \\ x(x + 3 \sqrt{2} ) -  \sqrt{2} (x + 3 \sqrt{2}) = 0 \\  \\( x -  \sqrt{2} ) \: (x +  3\sqrt{2} ) \\  \\ x =  \sqrt{2 \:}  \: and \: x =  - 3 \sqrt{2}
Thanks !

TANU81: ^_^
Answered by Vidhyasha
3
Hello dear I am tanwi and your answer is in u in photo


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