Question

$x ^{2} - 2 \sqrt{5 } - 15$
Solve it by middle term splitting ​

Answer 1

Answer:

The question might be wrong.

It should be,

$x ^{2} - 2x \sqrt{5} - 15$

To factorize it,

=

${x}^{2} - 2 \times x \times \sqrt{5} + 5 - 20$

${(x - \sqrt{5} )}^{2} - 20$

${(x - \sqrt{5} )}^{2} - ( \sqrt{20} ) ^{2}$

${(x - \sqrt{5}) }^{2} - {(2 \sqrt{5}) }^{2}$

$(x - \sqrt{5} - 2 \sqrt{5} )(x - \sqrt{5} + 2 \sqrt{5} )$

$(x - 3 \sqrt{5} )(x + \sqrt{5} )$

#BAL #answerwithquality