Question

${x}^{2} - 2x + 1 = 0$
Then
${x}^{2} + 1 \div {x}^{2} =$

Answer 1

x^2-2x+1

x^2-1x-1x+1

x(x-1)-1(x-1)
(x-1)=o
so x = 1
then
x^2+1/x^2=
(1)^2+1/(1)^2=
= 1
i think it help you

Answer 2

x² -2x+1 = 0
=> x² -x - x + 1 = 0
=> x( x-1) -1(x-1) =0
=> (x-1)(x-1) =0
=> x= 1 , x= 1

now, we have,
x= 1
putting this value in other equation.

x²+1/x²
=> 1² + 1/1²
=> 1+1
=> 2