Question

$(x ^{2} - 2x ^{2} + 5) \times (4x - 1)$
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Answer 1

Answer:

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Step-by-step explanation:

........

$( {x}^{2} - 2 {x }^{2} + 5) \times (4 x - 1) \\ =( 5 - {x}^{2} )(4x - 1) \\ \\ = 20x - 5 - 4 {x}^{3} + {x}^{2} \\ \\ = {x}^{2} - 4 {x}^{3} + 20x - 5 \\ \\ = {x}^{2} (1 - 4x) - 5(1 - 4x) \\ \\ = (1 - 4x)( {x}^{2} - 5) \\ \\ \\ (1 - 4x) = 0 \\ \\ ({x}^{2} - 5) = 0 \\ \\ so \: \: 1 = 4x = (x = 1 \div 4) \\ \\ and \\ \\ \: {x }^{2} = 5 = (x = \sqrt{5} )$

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x=+-√5,1/4