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Step-by-step explanation:
This is not factorable normally. We can see this since #x^2-2x+1# is a perfect square, so it touches the x-axis at a single root. Adding 1 to this produces #x^2-2x+2#, and raises the graph of #y = x^2-2x+1# one upwards, meaning it no longer touches the x-axis, so it has no real roots.
Answered by
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Step-by-step explanation:
x^2-2x^2-x+2
=-x^2-x+2
=-x^2-2x+x+2
=-x (x+2)+1 (x+2)
=(x+2)(-x+1)
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