![{x}^{2} - 2x - 46 = 0 {x}^{2} - 2x - 46 = 0](https://tex.z-dn.net/?f=%7Bx%7D%5E%7B2%7D+-+2x+-+46+%3D+0)
find x
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Answer:
This may help you
Step-by-step explanation:
x^2-2x-46=0
x=-(-2)+\-√-2^2-4×1×(-46)÷22×1
x=2+\-√4+184/2
x=2+\-√188/2
x=2+\-2√47
x=2+2√47
OR
x=2-2√47
x=1-√47. OR x=1+√47
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