Question

$x^2 + 2x + k =0$
If zeroes of are equal then find k​

Answer 1

Answer:

If zeros are equal then.!

D = 0

${2}^{2} - 4(1)(k) = 0 \\ 4 - 4k = 0 \\ k = 1$

#hope it help uh..

BRAINLIEST PLSS

Answer 2

HEY MATE!

HERE IS YOUR ANSWER:

If zeroes of the polynomial are equal then ,

Discriminant (D)=0

In x^2+2x+K=0 , a=1;b=2 and c=K

So, Discriminant (D)=b^2-4ac=0

So, (2)^2-4(1)(k)=0

4-4k=0

4(1-k)=0

1-k=0

-k=-1

k=1

HOPE IT HELPED ^_^