Question

$x ^{2} + 3 x ^{2} + 3x + 1 \div 5 + 9x$
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Answer 1

Answer:

${\bf 0.2 (20x^2 + 60x + 1)}$

Step-by-step explanation:

$\quad \bf x^{2} + 3 x^{2} + 3x + 1 \div 5 + 9x$

Collecting the like terms,

$\qquad : \implies \sf 4x^2 + 3x + 1 - 5 + 9x$

$\qquad : \implies \sf 4x^2 + 12x + 1 ÷ 5$

$\qquad : \implies \sf 4x^2 + 12x + \dfrac{1}{5}$

$\qquad : \implies \sf \dfrac{1}{5} \times (20x^2 + 60x + 1)$

$\large {\underline{\red{\boxed{\therefore \bf 0.2 (20x^2 + 60x + 1)}}}}$