Question

$x {}^{2} + 32x - 219 = 0$
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Answer 1

Answer:

$x = - 16 + 5 \sqrt{19} \\ or \\ x = - 1 6 - 5 \sqrt{19}$

Step-by-step explanation:

we have given

${x}^{2} + 32x - 219 = 0$

we have formula for quadratic equation,

$x = \frac{ - b + \sqrt{ {b }^{2} - 4 ac} }{2a} or \: \frac{ - b - \sqrt{ {b}^{2} - 4ac } }{2a}$

fill in all values,

we get,

$x = \frac{ - 32 + \sqrt{ {32}^{2} - 4 \times - 219} }{2} or \frac{ - 32 - \sqrt{ {32}^{2} - 4 \times - 219} }{2}$

$x = \frac{ - 32 + \sqrt{1024 + 876} }{2} or \frac{ - 32 - \sqrt{1024 + 876} }{2}$

$x = \frac{ - 32 + \sqrt{1900} }{2} or \frac{ - 32 - \sqrt{1900} }{2}$

$x = -16 + 5 \sqrt{19} \: or \: - 16 - 5 \sqrt{19}$