Question

${x}^{2} - 36 = 0$
solve by quadratic formula? ​

Answer 1

.i hope you understand..

Answer 2

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To Solve:

• ${x}^{2} - 36 = 0$

Solution:

$:\longrightarrow x^2 - 36 = 0 \\\\:\implies x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\\\\text{Here, a=coefficient of x ^2 =1, b=coefficient of x=0, c=constant=-36} \\\\:\implies x = \dfrac{0 \pm \sqrt{0^2 - 4(1)(-36)}}{2(1)} \\\\:\implies x = \dfrac{\pm \sqrt{4*36}}{2} \\\\:\implies \dfrac{\pm 2 * 6}{2} \\\\\bf{:\implies x = \pm 6}$

Hope it helps!!!