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Solution:-
=> x² - 3x + 2
=> x² - 2x - x + 2
=> x ( x - 2 ) - 1 ( x - 2 )
=> ( x - 1 ) ( x - 2 )
let,
=> x - 1 = 0 or x - 2 = 0
=> x = 1 or x = 2
i hope it helps you.
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