Math, asked by Manishadharman, 1 year ago


 {x}^{2}  - 3x + 2
ans?​

Answers

Answered by paryuljain23
1

x² - 3x + 2 = 0

x² - x - 2x + 2 = 0

x(x - 1) -2(x - 1) = 0

x = 1,2

Answered by anurag7315
0

Answer:

x=1,2

Step-by-step explanation:

 {x}^{2}  - 3x + 2 = 0 \\  {x}^{2}   - x - 2x + 2 = 0 \\ x(x - 1) - 2(x - 1) = 0 \\ (x - 1) \times (x - 2) = 0 \\ either \: (x - 1) = 0 \:  \:  \:  \:  \:  \:  ==> x = 1 \\ or \: (x - 2) = 0 \:  \:  \:  \:  ==> x = 2

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