Question

${x}^{2} + 4x + 1 = 0$
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Answer 1

Step-by-step explanation:

$\huge\bf{\mid{\overline{\underline{ANSWER:-}}\mid}}$

$Above \: is \: the \: expression \: of \: quadratic \: equation \\ \\ {x}^{2} + 4x +1 =0 \\ \\ Comparing \: with \implies \\ \\ a{x}^{2} + bx +c = 0 \\ \\ a = 1 \\ b = 4 \\ c = 1 \\ \\ x = \frac{-b \pm \sqrt{{b}^{2} - 4ac}}{2a} \\ \\ x = \frac{ -4 \pm \sqrt{16 - 4}}{2} \\ \\ x = \frac{ -4 \pm \sqrt{ 12}}{2} \\ \\ x = \frac{ -4 \pm 2 \sqrt{3}}{2} \\ \\ x = \cancel{2} \times \frac{ -2 \pm \sqrt{3}}{\cancel{2}} \\ \\ \huge\boxed{ x = - 2 \pm \sqrt{3} }$