Question

$x^{2} +5x-24=0$
if k is a solution of the equation above and k is negative, what is the value of l $k$l

Answer 1

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${x}^{2} + 5x - 24 = 0 \\ {x}^{2} + 8x - 3x - 24 = 0 \\ x( x + 8) - 3(x + 8) = 0 \\ (x + 8)(x - 3) = 0 \\ x = 3 \: \: \: and \: \: \: x = - 8 \: \: \\ so \\ \\ k = 8 \: \: ans \:$

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Answer 2

Given :   x² + 5x - 24  = 0  k is a solution of the equation and k is negative

To find : | k |

Solution:

x² + 5x - 24  = 0

k is a solution of the equation   and k is negative

First find solution of Equation  x² + 5x - 24  = 0

x²  + 8x - 3x - 24 = 0

=> x(x + 8) - 3(x + 8) = 0

=> (x - 3)(x + 8) = 0

= x = 3  , x = -8

only negative solution is - 8

=> k = - 8

| k |  = | - 8 |   = 8

| k |  = 8

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