Question

$x {}^{2} - 5x + 3 = 0$

solve by quadractic equation​

Answer 1

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

Above Equation is a quadratic equation so,we solve it through quadratic formula simply it can't be factorise because there is no such factors found.

➙x²-5x+3=0

a= 1 ,b= -5 & c= 3

x= -b±√b²-4ac ÷ 2a

➙x= -(-5)±√(-5)²-4(1)(3)/2(1)

➙x= 5±√ 25-12/2

➙x=5±√13/2

Since,the discriminant b²-4ac is > 0

So,there are two real roots.

➙x= 5±√13 / 2

➙x= 5/2 ± √13/2

➙x= 4.30 or x=0.69

Hence, x is 4.30 or 0.69

Answer 2

So,there are two real roots.

➙x= 5±√13 / 2

➙x= 5/2 ± √13/2

➙x= 4.30 or x=0.69

Hence, x is 4.30 or 0.69