Math, asked by Kavithamohan894, 2 months ago


x {}^{2} - 5x + 3 = 0

solve by quadractic equation​

Answers

Answered by Flaunt
13

\sf\huge\bold{\underline{\underline{{Solution}}}}

Above Equation is a quadratic equation so,we solve it through quadratic formula simply it can't be factorise because there is no such factors found.

➙x²-5x+3=0

a= 1 ,b= -5 & c= 3

x= -b±√b²-4ac ÷ 2a

➙x= -(-5)±√(-5)²-4(1)(3)/2(1)

➙x= 5±√ 25-12/2

➙x=5±√13/2

Since,the discriminant b²-4ac is > 0

So,there are two real roots.

➙x= 5±√13 / 2

➙x= 5/2 ± √13/2

x= 4.30 or x=0.69

Hence, x is 4.30 or 0.69

Answered by vaishnavisinghscpl45
0

So,there are two real roots.

➙x= 5±√13 / 2

➙x= 5/2 ± √13/2

➙x= 4.30 or x=0.69

Hence, x is 4.30 or 0.69

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