solve by quadractic equation
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Above Equation is a quadratic equation so,we solve it through quadratic formula simply it can't be factorise because there is no such factors found.
➙x²-5x+3=0
a= 1 ,b= -5 & c= 3
x= -b±√b²-4ac ÷ 2a
➙x= -(-5)±√(-5)²-4(1)(3)/2(1)
➙x= 5±√ 25-12/2
➙x=5±√13/2
Since,the discriminant b²-4ac is > 0
So,there are two real roots.
➙x= 5±√13 / 2
➙x= 5/2 ± √13/2
➙x= 4.30 or x=0.69
Hence, x is 4.30 or 0.69
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So,there are two real roots.
➙x= 5±√13 / 2
➙x= 5/2 ± √13/2
➙x= 4.30 or x=0.69
Hence, x is 4.30 or 0.69
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