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Answered by
1
Hey user here is your answer.....
---->Given equation - x^2+5x+4
---->To find - x
◆By middle term splitting
x^2+4x+x+4
◆Take common
◆x(x+4)+1(x+4)
◆(x+1)(x+4)
◆x+1=0
&
◆x+4=0
◆x=-1 & x=-4
Thanks☺️
#Rohan
---->Given equation - x^2+5x+4
---->To find - x
◆By middle term splitting
x^2+4x+x+4
◆Take common
◆x(x+4)+1(x+4)
◆(x+1)(x+4)
◆x+1=0
&
◆x+4=0
◆x=-1 & x=-4
Thanks☺️
#Rohan
Answered by
1
Heya !!!
This is Your Answer..
Given :-
x² + 5x + 4
We have to look for two numbers a and b such that a+b = 5 and ab = 4.
Now, looking at prime factorisation of 4...
4 = 1 X 2 X 2.
Hence, we get a = 1 and b = 2X2 = 4.
So,
x² + 5x + 4
= x² + 4x + x + 4
= x (x + 4) + 1 (x + 4)
= (x+1) (x + 4)
x = -1 Or x = -4.
Hope It Helps
This is Your Answer..
Given :-
x² + 5x + 4
We have to look for two numbers a and b such that a+b = 5 and ab = 4.
Now, looking at prime factorisation of 4...
4 = 1 X 2 X 2.
Hence, we get a = 1 and b = 2X2 = 4.
So,
x² + 5x + 4
= x² + 4x + x + 4
= x (x + 4) + 1 (x + 4)
= (x+1) (x + 4)
x = -1 Or x = -4.
Hope It Helps
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