Math, asked by geakansh9, 3 months ago

$x {}^{2} - 5x - 6 = 0$

Answers

Answered by chauhanaaditya43

2

Answer:

${x}^{2} - 5x - 6 = 0\\ {x}^{2} - 6x + 1x - 6 = 0 \\ x(x - 6) + 1(x - 6) = 0 \\( x + 1)(x - 6) = 0 \\ x = 6 \: or - 1.$

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