by prime factorisation method
Answers
Answered by
1
Answer:
here, (x-2)(x-3) =0
=> x = 2 or, 3
Answered by
4
Solution
x²-5x+6=0
(applying prime factorisation method....)
=>x²-(3+2)x+6=0
=>x²-3x-2x+6=0
=>X(x-3)-2(x-3)=0
=>(x-3)(x-2)=0
Either,
(x-3)=0
=>X=3
or,
(x-2)=0
=>X=2
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