![{x}^{2} - 6 \: \sqrt[]{x + 2 = 0} {x}^{2} - 6 \: \sqrt[]{x + 2 = 0}](https://tex.z-dn.net/?f=+%7Bx%7D%5E%7B2%7D+-+6++%5C%3A+++%5Csqrt%5B%5D%7Bx+%2B+2+%3D+0%7D+)
Solve the equation
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Answer:
Your answer is 2²x-3
Step-by-step explanation:
Hope it helps....
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