Question

$x {}^{2} - 7x {}^{2} + 1$
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Answer 1

${\tt{\purple{\underline{\underline{\huge{Answer♡}}}}}}$

$\implies\sf {x}^{2} - {7x}^{2} + 1 = 0$

$\implies\sf { - 6x}^{2} + 1 = 0$

$\implies\sf { - 6x}^{2} = - 1$

$\implies\sf {x}^{2} = \dfrac{ - 1}{ - 6}$

$\implies\sf {x}^{2} = \dfrac{1}{6}$

$\implies\sf \: x = \sqrt{ \dfrac{1}{6} }$

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