Question

$x ^{2} + 7x - 3 = (x + 8) ^{2}$
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Answer 1

Step-by-step explanation:

Given, x² + 7x - 3 = (x + 8)²

=> x² + 7x - 3 = x² + 16x + 64

=> 7x - 3 = 16x + 64

=> 7x - 16x = 3 + 64

=> -9x = 67

=> x = -67/9

Answer 2

Given -

• $\bf{\ x^{2} +7x-3 = \ (x+8)^{2}}$

To Find -

• $\bf{Value\:of\:x}$

Solution -

• Here, we have to find the value of x by solving this given equation

$\sf{\boxed{\boxed{\ (a+b)^2 = \ a^{2} + \ b^{2}+2ab}}}$

$\mapsto\sf{\ x^{2} +7x-3 = \ (x+8)^{2}}$

$\mapsto\sf{\ x^{2} +7x-3 = \ x^{2}+64+16x}$

• $\sf{\ x^{2} }$ will cancel each other

$\mapsto\sf{7x-16x = 64+3}$

$\mapsto\sf{-9x = 67}$

$\mapsto\sf{x = - \dfrac{67}{9}}$

So , value of x is $\sf{-\dfrac{67}{9}}$