Question

$x^2+7x=8 find x$

Answer 1

x²+7x=8

=>x²+7x-8=0

=>x²+8x-x-8=0

=>x(x+8)-1(x+8)=0

=>(x-1)(x+8)=0

=>x=1 OR -8

Answer 2

QUESTION:

${x}^{2} + 7x = 8 \\ {x}^{2} + 7x - 8 = 0$

solve for x.

ANSWER:

In order to find x we have to factorised it.

quadratic equations is in the form of

$a {x}^{2} + bx + c = 0$

STEP 1 :

Split the middle term in such a way that it's sum equal to b i.e. . +7 and product will be a ×c.

${x}^{2} +8x -x - 8$

TAKING common factor

$x(x + 8) - 1(x +8)$

$(x - 1)(x + 8) \: are \: the \: factors$

now.

EITHER

$x - 1 = 0 \\ x = 1$

OR

$x +8 = 0 \\ x = -8$

FINAL ANSWER :

$\huge\red{x = 1 \: or \: -8}$

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