Question

${x}^{2} + 7x + 9$
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Answer 1

 $\displaystyle\sf{Given,$

$\displaystyle\sf{x^2+7x+9=0$

$\displaystyle\sf{Here,x\:can\:be\:determined\:by\:the\:equation:$

$\boxed{\displaystyle\sf{x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}}}$

$\displaystyle\sf{Here,$

• $\displaystyle\sf{a=1$

• $\displaystyle\sf{b=7$

• $\displaystyle\sf{c=9$

$\displaystyle\sf{Substituting\:the\:values\:to\:the\:equation,$

$\displaystyle\sf{\implies x=\frac{-7\pm\sqrt{49-(4\times1\times9)}}{(2\times1)}$

$\displaystyle\sf{\implies x=\frac{7\pm\sqrt{49-36}}{2}$

$\displaystyle\sf{\implies x=\frac{7\pm\sqrt{13}}{2}$

$\boxed{\displaystyle\sf{ x=\frac{7\pm\sqrt{13}}{2}\:\:\:is\:the\:root\:of\:the\:equation.}}$

Answer 2

Step-by-step explanation:

hey mate here is the correct answer