Math, asked by sarikakamble193, 10 months ago

$x {}^{2} { + 8x - 4 = 0}$
completing square method

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Answered by Lekhashree11

1

HOPE THIS HELPS YOU............

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Answered by agamdeep34

4

Answer:

$x {}^{2} + 8x - 4 = 0 \ \{ x \times x + 2 \times 2 \} 2x - 2 \times 2 = 0 \\{ x + 2} \: \\ {x + 2} \: 2{x - 2}$

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