Math, asked by devesh200576, 9 months ago


 {x}^{2}  + 92 {y}^{2}  = 1
who can answer this question
I will give you 100 points​

Answers

Answered by princetyagi368
1

ANSWER:

☆X^2-92Y^2 = 1

Using identity, a^2-b^2 = (a-b) (a+b)

=> (x+ root 92) (x- root 92) = 1

=> (x+ 2root 23) (x-2root 92) =1

Therefore, x+ 2root23=1 => x=1-2root23

x- 2root23=1 => x=1+2root23

Answered by Anonymous
0

Answer:

\tt{x^{2} - 92y^{2} = 1}

a^2 - b^2 = (a + b)(a - b)

=> \tt{(x- \sqrt{92}y)(x+\sqrt{92}y) =1}

=> \tt{x = 1 + \sqrt{92}y, 1 - \sqrt{92}y}

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