Question

$({x}^{2} + \frac{1}{x {}^{2} } ) = 146 \: find \: the \: value \: of \: (x {}^{4} + \frac{1}{x {}^{4} } )$
plesae solve

Answer 1

$x {}^{2} + \frac{1}{x {}^{2} } = 146 \\ \\ squaring \: \: both \: \: + sides \\ \\ (x {}^{2} + \frac{1}{x {}^{2} } ) {}^{2} = (12) {}^{2} \\ \\ x {}^{4} + \frac{1}{x {}^{4} } + 2 = 144 \\ \\ x {}^{4} + \frac{1}{x {}^{4} } = 144 - 2 \\ \\ x {}^{4} + \frac{1}{x {}^{4} } = 142$


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Answer 2

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