Question

$x ^{2} + \frac{1}{x {}^{2} } - 2 - 3x + \frac{3}{x}$
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Answer 1

$x^{2} + \frac{1}{x {}^{2} } - 2 - 3x + \frac{3}{x} \\ {(x + \frac{1}{x} )}^{2} - 3(x + \frac{1}{x} ) \\ (x + \frac{1}{x} )(x + \frac{1}{x} - 3)$

Formula used

(x + 1/x)^2 = x^2 + 1/x^2 +2

Answer 2

Answer:

Hello mate

Refer to attachment