Question

${x}^{2} + \frac{12}{35} x + \frac{1}{35}$
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\huge{\pink{\boxed{\green{\underline{\sf{x=\frac{-1}{7},\frac{-1}{5}}}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

☆ Correction in question:

$\to {x}^{2} + \frac{12x}{35} + \frac{1}{35} = 0$

☆ According to given question:

$\: \: \: \: \: \: { \orange{given}} \\ {\pink{\boxed {\green{ {x}^{2} + \frac{12x}{35} + \frac{1}{35} = 0}}}} \\ \\ \: \: \: \: \: { \blue{to \: find}} \\ { \purple {\boxed{ \red{value \: of \: x = }}}}$

☆ Using method middle term spliting to solve:

$\to {x}^{2} + \frac{12x}{35} + \frac{1}{35} = 0 \\ \to \frac{35 {x}^{2} + 12x + 1 }{35} = 0 \\ \to35 {x}^{2} + 12x + 1 = 0 \\ \to {35x}^{2} + 7x + 5x + 1 = 0 \\ \to7x(5x + 1) + 1(5x + 1) = 0 \\ \\ \to 7x + 1 = 0 \\ \to7x = - 1 \\ { \pink{ \boxed{ \green{\to x = \frac{ - 1}{7} }}}} - - - - - 1st \: value \\ \\ \to 5x + 1 = 0 \\ \to5x = - 1 \\ { \pink{ \boxed{ \green{\to x = \frac{ - 1}{5}}}}} - - - - - 2nd \: value$

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