Question

${x}^{2} + \sqrt{ - 1 {}^{2} } {y }^{2} = \frac{16}{9} + \frac{9}{25} \sqrt{ - 1}$
need answer
a,
$x = \frac{4}{3} \\ y = \frac{3}{5}$
b,
$x = \frac{6}{3} \\ y = \frac{9}{3}$
c,
$x = \frac{2}{5} \\ y \frac{6}{3}$

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Answer 1

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