Question

${x}^{2} - ( \sqrt{2} + i)x + \sqrt{2}i = 0$
Using Quadric Formula.​

Answer 1

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Answer 2

${ \bf{ \huge{\underline{ \pink{\underline{\red{solution} : }}}} - } } \\ \\ </p><p>{\mathtt { \dashrightarrow{ \purple{ {x}^{2} -( \sqrt{2} + i \: )x \: + \: \sqrt{2} \: i = 0}}}} \\ {\mathtt{ \underline{ \pink{we \: can \: write \: is \: as}}}}\\ {\mathtt { \dashrightarrow{ \purple{ {x}^{2} - ( i + \sqrt{2})x + \sqrt{2} \: \: \: i = \: 0}}}} \\ \\ {\mathtt { \dashrightarrow{ \purple{ {x}^{2} - i \:x - \sqrt{2 } \: x + \sqrt{2} \: i \: = \: \: 0}}}} \\ \\ {\mathtt { \dashrightarrow{ \purple{ x(x - i) \: - \: \sqrt{2} \: (x - i) \: \: = \: \: 0}}}} \\ \\ {\mathtt { \dashrightarrow{ \purple{(x - \sqrt{2} ) \: (x - i) \: \: = \: \: 0}}}} \\ \\ {\mathtt { \dashrightarrow{ \purple{(x - \sqrt{2} ) \: = \: \: 0\: \: { \red{or}} \: \: (x - i) \:= \: \: 0}}}} \\ \\ {\mathtt { \dashrightarrow{ \purple{x = \sqrt{2} \: \: \: \: { \red{or }} \: \: \: \: x = i }}}} </p><p></p><p>$

Note:- " i " is imaginary number.

i hope it helps you.