Find Factorization
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5
Heya !!
X² - √2X - 3/2
2X² - 2√2X - 3 = 0
2X² - 3√2X + √2X - 3
√2X ( √2X - 3 ) +1 ( √2X - 3 )
( √2X - 3 ) ( √2X + 1 ) [ Answer ]
X² - √2X - 3/2
2X² - 2√2X - 3 = 0
2X² - 3√2X + √2X - 3
√2X ( √2X - 3 ) +1 ( √2X - 3 )
( √2X - 3 ) ( √2X + 1 ) [ Answer ]
anubhav829:
hi
Answered by
2
Hi,
Here is your answer,
→ x²-√2x-3/2
→ 2x²-2√2x-3 = 0 It is in the form of ax² + bx + c = 0
→ ((2x²)- 3√2x + √2x- 3)
→ √2x(√2x-3) +1 (√2x-3)
→ (√2x-3) (√2x+1)
Hope it helps you !
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