Question

$x = 2 + \sqrt{3} \: then \: {x}^{3} 4 \times \frac{1}{ {x}^{3} }$
what solve the problems​

Answer 1

Answer:

As x=2 +root 3

x cube= (2+root3)^3

=2^3+ 2× 2× root 3 + root3^3

if we apply our common sense

=(2+root3)^3 ×4 ×1/(2+root3)^3

=4

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Important formula:

(a+b)^3= (a+b) (a^2+ab+b^2)