Question

${x}^{2}$
-25/9​

Answer 1

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${x}^{2} - \frac{25}{9}$

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${a}^{2} - {b}^{2} = (a + b)(a - b)$

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${x}^{2} - \frac{25}{9}$

$= {x}^{2} - ( \frac{5}{3} ) {}^{2}$

$= (x + \frac{5}{3} )(x - \frac{5}{3} )$

Answer 2

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Given:

• $x^2 - \dfrac{25}{9}$

Solution:

$\longrightarrow x^2 - \dfrac{25}{9} \\\\\implies x^2 - \dfrac{5^2}{3^2} \\\\\implies x^2 - \left(\dfrac{5}{3}\right)^2 \\\\\bf{\implies \left(x - \dfrac{5}{3}\right)\left(x + \dfrac{5}{3}\right)} </p><p>$

Formula used:

• a^2 - b^2 = (a+b)(a-b)

Learn More:

$\boxed{\begin{minipage}{7 cm}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identity}}\:\bigstar}\\\\1)\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2)\bf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3)\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\4)\bf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\5)\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\6)\bf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7)\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) - B^{3}\\\\8)\bf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\9)\bf\: A^{3} - B^{3} = (A-B)(A^{2} + AB + B^{2})\\\\ \end{minipage}}$