Math, asked by oraonraghu, 8 months ago


x {}^{2} \times (y {}^{2}  - z {}^{2} ) + y {}^{2} (z {}^{2}  - y {}^{2} ) + z {}^{2} (x {}^{2}  - y {}^{2} )

Answers

Answered by varunvbhat26
0

If you mean the question is this:

x^{2} \times (y^{2} - z^{2} ) + y^{2} \times (z^{2} - x^{2}) + z^{2} \times (x^{2} - y^{2})

then the answer's this:

= x^{2}y^{2} - x^{2} z^{2} + y^{2}z^{2} - x^{2} y^{2}  + x^{2} z^{2} - y^{2}z^{2}

= x^{2}y^{2} - x^{2} y^{2} + y^{2}z^{2} - y^{2} z^{2}  + x^{2} z^{2} - x^{2}z^{2}

= 0

If you mean the question is this:

x^{2} \times (y^{2} - z^{2} ) + y^{2} \times (z^{2} - y^{2}) + z^{2} \times (x^{2} - y^{2})

then the answer's this:

= x^{2}y^{2} - x^{2} z^{2} + y^{2}z^{2} - y^{4}  + x^{2} z^{2} - y^{2}z^{2}

= x^{2}y^{2} - y^{4} + y^{2}z^{2} - y^{2} z^{2}  + x^{2} z^{2} - x^{2}z^{2}

= x^{2}y^{2} - y^{4}

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