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18
Answered by
0
Answer:
x
2
+x+1=0
{x}^{2} + (1 + 1)x + 1 = 0x
2
+(1+1)x+1=0
{x}^{2} + 1x + 1x + 1 = 0x
2
+1x+1x+1=0
x(x + 1)(x + 1) = 0x(x+1)(x+1)=0
x + 1 = 0x+1=0
Step-by-step explanation:
hope it's helpful ☺️
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