Math, asked by shailashb945, 7 months ago


x ^{2}  + x + 1 = 0



Answers

Answered by itzinnocentdevil
18

 \huge \bold \red{answer}

 {x}^{2}  + x \: + 1 = 0

 {x}^{2}  + (1 + 1)x + 1 = 0

 {x}^{2}  + 1x + 1x + 1 = 0

x(x + 1)(x + 1) = 0

x + 1 = 0

Answered by Anonymous
0

Answer:

x

2

+x+1=0

{x}^{2} + (1 + 1)x + 1 = 0x

2

+(1+1)x+1=0

{x}^{2} + 1x + 1x + 1 = 0x

2

+1x+1x+1=0

x(x + 1)(x + 1) = 0x(x+1)(x+1)=0

x + 1 = 0x+1=0

Step-by-step explanation:

hope it's helpful ☺️

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