Question

$x { }^{2} - x - 12 = 0 \\ y {}^{2} + 5y - 6 = 0$
+4. -3
-3. -2
x=y​

Answer 1

Answer:

x - y = 4

y = mx + b

The first step we need to do is isolate the y term

add-x to both sides

-y=-x+4

Divide all terms by -1

 

y=x-4 m = the coefficient of x=1

b=-4

Step-by-step explanation: